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Solve the inequation `log_(2x+3)x^(2)ltlog_(2x+3)(2x+3)` |
Answer» This inequation is equivalent to the collection of the systems `[{(2x+3gt1),(x^(2)lt2x+3),(0lt2x+3lt1),(x^(2)gt2x+3):}implies[{(xgt-1),((x-3)(x+1)lt0):},{((-3/2ltxlt-1),((x-3)(x+1)gt0):}):}` `implies[{(xgt-1),(-1ltxlt3):}, {(-3/2lt x lt-1),(xlt-1 "and" xgt3)implies-3/2ltxlt-1):}` Hence the solution of the original inequation is `x epsilon(-3/2,-1)uu(-1,3)`. |
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