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Answer» time taken by car A and car B be x secondsTotal distance covered by car A in x SECONDS = 10x mSo TOTAL distance covered by Car B(in order to chase the car) in x seconds = 10.5+ 10xm --(1)As B "has to chase" Car ASince the SLOPE of velocity- time in Car is 45 degree THENTAN 45 = 1 so final velocity and time is equal to xm/sBy the formulaS = ut+1/2 at^2s = 10.5+10x mu =0A = v-u/t = x /x =1m/st = x second10.5+10x = 0 × t + 1/2 × 1 × (x)^210.5 +10x = (x)^2/ 2x^2 = 2(10.5+10x)x^2 = 21+20xx^2-20x-21 =0By splitting middle term.x^2 +x-21x-21 =0( x-21 )(x+1) =0x -21=0 and x+1 =0x =21 x=-1Since x can't be negativeTHEREFORE TIME TAKEN IS 21 SECONDSMARK AS BRAINLIEST PLEASE FOLLOW ME |
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