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Answer» <html><body><p>time taken by car A and car B be x secondsTotal distance covered by car A in x <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a> = 10x mSo <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> distance covered by Car B(in order to chase the car) in x seconds = 10.5+ 10xm --(1)As B "has to chase" Car ASince the <a href="https://interviewquestions.tuteehub.com/tag/slope-15649" style="font-weight:bold;" target="_blank" title="Click to know more about SLOPE">SLOPE</a> of velocity- time in Car is 45 degree <a href="https://interviewquestions.tuteehub.com/tag/thentan-3201223" style="font-weight:bold;" target="_blank" title="Click to know more about THENTAN">THENTAN</a> 45 = 1 so final velocity and time is equal to xm/sBy the formulaS = ut+1/2 at^2s = 10.5+10x mu =<a href="https://interviewquestions.tuteehub.com/tag/0a-256457" style="font-weight:bold;" target="_blank" title="Click to know more about 0A">0A</a> = v-u/t = x /x =1m/st = x second10.5+10x = 0 × t + 1/2 × 1 × (x)^210.5 +10x = (x)^2/ 2x^2 = 2(10.5+10x)x^2 = 21+20xx^2-20x-21 =0By splitting middle term.x^2 +x-21x-21 =0( x-21 )(x+1) =0x -21=0 and x+1 =0x =21 x=-1Since x can't be negativeTHEREFORE TIME TAKEN IS 21 SECONDSMARK AS BRAINLIEST PLEASE FOLLOW ME</p></body></html>


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