Solve : `(x+y)dy+(y-2x)dx=0` – InterviewSolution

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1.	Solve : `(x+y)dy+(y-2x)dx=0`
Answer» Correct Answer - `y^(2)+2xy-2x^(2)=C` `int(v+1)/(v^(2)+2v-2)dv=-int(dx)/(x) rArr 1/2 int (2v+2)/(v^(2)+2v-2) dv= -int (dx)/x` `therefore 1/2log\|v^(2)+2v-2\|+log\|x\|=log\|C_(1)\|`.

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