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`(x-y)dy-(x+y)dx=0` |
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Answer» Correct Answer - `tan^(-1)y/x=1/2log(x^(2)+y^(2))+C` `int(1-v)/(1+v^(2))dv=int1/xdx rArr int(dv)/(1+v^(2))-1/2int(2v)/(1+v^(2))dv=int1/xdx`. `therefore tan^(-1)v-1/2log(1+v^(2))=log|x|+C rArr tan^(-1)y/x=1/2log(x^(2)+y^(2))+C`. |
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