Solve: x3 + y3 = 3axy

1.	Solve: x3 + y3 = 3axy
Answer» Given x³ + y³ = 3axy 3x² + 3y²\(\frac{dy}{dx}\) = 3a(x .\(\frac{dy}{dx}\) + y.1) \(\frac{dy}{dx}\)(3y² – 3ax) = 3ay – 3x² = \(\frac{dy}{dx}\) = \(\frac{ay - x^2}{y^2 - ax}\)

Answer»

Given x³ + y³ = 3axy

3x² + 3y²\(\frac{dy}{dx}\) = 3a(x .\(\frac{dy}{dx}\) + y.1)

\(\frac{dy}{dx}\)(3y² – 3ax) = 3ay – 3x² = \(\frac{dy}{dx}\)

= \(\frac{ay - x^2}{y^2 - ax}\)

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