Specific heat of an elementary gas is found to be 0.313 J at constant volume. If the molar mass of the gas is 40 g `mol^(-1)` , what is the atomicity of the gas ?

Specific heat of an elementary gas is found to be 0.313 J at constant

1.	Specific heat of an elementary gas is found to be 0.313 J at constant volume. If the molar mass of the gas is 40 g `mol^(-1)` , what is the atomicity of the gas ?
Answer» Correct Answer - monoatomic `C_(v) = 0.313 xx 40 = 12.52J mol^(-1) , C_(p) = C_(v)+R = 12.52 + 8.31= 20.83J mol^(-1)` `:. C_(p) //C_(v) = 20.83 // 12.52 = 1.66`

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Specific heat of an elementary gas is found to be 0.313 J at constant volume. If the molar mass of the gas is 40 g `mol^(-1)` , what is the atomicity of the gas ?

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