1.

Specific resistance of the wire is 44 x 10^-8 ohm m. Ifthe resistance of the wire is 14 ohm and its diameter10^-3 m, calculate the length of the wire. [Ans. 25 m]

Answer»

Given :

resistivity of the conductor = 44 * 10^-8 ohm m.

R = 14 ohm

Diameter = 1mm

Area = πD^2/4 = π/4 * (10^-3)^2 m^2

we know that,

length of wire = resistance * area/ resistivity of the conductor

=. 14 * π/4 * (10^-6)* 1/44*10^-8

= 14 * (22/7*4 )* 10^-6 *1/44*10^-8

= 14 * 22/28 * 100/44

= 22/2 * 100/44

= 100/4

= 25m



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