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`sqrt(((1+sin2theta))/(1-cos^(2)theta))["where" theta in [0,(pi)/(4)]]=`A. `"cosec"^(2) theta `B. `1`C. `1+ cot theta `D. `1+ tan theta ` |
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Answer» Correct Answer - C `1+ sin 2 theta =( sin theta + cos theta )2, " when" theta in[0,(pi)/(4)]`. |
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