InterviewSolution
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InterviewSolution
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Standard entropies of `X_(2), Y_(2)` and`XY_(3)` are 60,40 and `50JK^(-1)mol^(-1)` respectively. For the reaction (1)/(2)X_(2) + (3)/(2)Y_(2) hArr XY_(3) , DeltaH= - 30 kJ ` to be at equilibrium , the temperature should beA. 500KB. 750 KC. 1000KD. 1250 K |
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Answer» Correct Answer - b `(1)/(2) X_(2) + ( 3)/(2)Y_(2) hArr XY_(3)` `DeltaS^(@) = SigmaS_(P)^(@) - Sigma _(R)^(@) = 50-( 30+60) = - 40 JK^(-1) mol^(-1)` `DeltaG^(@) =DeltaH^(@) - T DeltaS^(@) ` . At equilibrium , `DeltaG^(@) = 0`. Hence,`TDeltaS^(@) = DeltaH^(@)` or `T= (DeltaH^(@))/( DeltaS^(@)) = ( -30 xx 10^(3) J mol^(-1))/( -40JK^(-1) mol^(-1))= 750 K` |
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