starting from a stationary position, rajan drive his scooter to attain a velocity 600 m/s in 30 sec. then he applies breaks such that velocity of scooter comes down to 400 m/s in the next 5 sec. calculate the acceleration of scooter in both cases.

starting from a stationary position, rajan drive his scooter to attain

1.	starting from a stationary position, rajan drive his scooter to attain a velocity 600 m/s in 30 sec. then he applies breaks such that velocity of scooter comes down to 400 m/s in the next 5 sec. calculate the acceleration of scooter in both cases.
Answer» t case rajan STARTS from rest and gains 600 m/s velocity in 30 seconds. u = 0v = 600 m/ST = 30 sa = v-u/t (or u can use 1 st equation of motion v=u+at) = 600-0/30 = 600/30 = 20 m/s²In the SECOND case rajan's speed decreases from 600 m/s to 400 m/s in 5 seconds. u = 600 m/sv = 400 m/st = 5 sa = v-u/t = 400-600/5 = -200/5 = -40 m/s² (-ve SIGN indicates that it is performing RETARDATION)

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starting from a stationary position, rajan drive his scooter to attain a velocity 600 m/s in 30 sec. then he applies breaks such that velocity of scooter comes down to 400 m/s in the next 5 sec. calculate the acceleration of scooter in both cases.

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