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Starting with one mole of a compound `A`, it is found that the reaction is `3//4` completed in `1 hr`. Find the rate constant if the reaction is of `II` order.A. 2.31 `"min"^(-1)`B. `0.231 "min"^(-1)`C. `0.0231 "min"^(-1)`D. `0.00231 "min"^(-1)` |
Answer» Correct Answer - c `K =- (2.303)/(t)` log `(a)/(a-x)` `k = (2.303)/(60)` log `(1)/(1-3//4)` `K = (2.303)/(60)` log 4 = `0.0231` . |
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