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                                    State whether the following quadratic equations have two distinct real roots. Justicy your answer: `(x+1)(x-2)+x=0` | 
                            
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Answer» Given equation is `(x+1)(x-2)+x=0` `implies x^(2)+x-2x-2+x=0` `implies x^(2)-2=0` `implies x^(2)+0.x-2=0` On comparing with `ax^(2)+bx+c=0` we get `a=1, b=0` and `c=-2` `:.` Discriminant ` D=b^(2)-4ac=(0)^(2)-4(1)(-2)=0+8=8gt0` Hence the equation `(x+1)(x-2)+x=0` has two distinct real roots.  | 
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