

InterviewSolution
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Subtract the first rational number from the second in each of the following:(i) \(\frac{3}{8}, \frac{5}{8}\)(ii) \(\frac{-7}{9}, \frac{4}{9}\)(iii) \(\frac{-2}{11}, \frac{-9}{11}\)(iv) \(\frac{11}{13}, \frac{-4}{13}\)(v) \(\frac{1}{4}, \frac{-3}{8}\)(vi) \(\frac{-2}{3}, \frac{5}{6}\)(vii) \(\frac{-6}{7}, \frac{-13}{14}\)(viii) \(\frac{-8}{33}, \frac{-7}{22}\) |
Answer» (i) \(\frac{5}{8}-\frac{3}{8}\) = \(\frac{5-3}{8}\) = \(\frac{2}{8}\) (Therefore, L.C.M of 8 and 8 is 8) = \(\frac{1}{4}\) (ii) \(\frac{4}{9}-\frac{-7}{9}\) = \(\frac{4+7}{9}\) = \(\frac{11}{9}\) (Therefore, L.C.M of 9 and 9 is 9) (iii) \(\frac{-9}{11}-\frac{-2}{11}\) = \(\frac{-9+2}{11}\) = \(\frac{-7}{11}\) (Therefore, L.C.M of 11 and 11 is 11) (iv) \(\frac{-4}{13}-\frac{11}{13}\) = \(\frac{-4-11}{13}\) = \(\frac{-15}{13}\) (Therefore, L.C.M of 13 and 13 is 13) (v) \(\frac{-3}{8}-\frac{1}{4}\) = \(\frac{-3-2}{8}\) = \(\frac{-5}{8}\) (Therefore, L.C.M of 8 and 4 is 8) (vi) \(\frac{5}{6}-\frac{-2}{3}\) = \(\frac{5+4}{6}\) = \(\frac{9}{6}\) (Therefore, L.C.M of 6 and 3 is 6) (vii) \(\frac{-13}{14}-\frac{-6}{7}\) = \(\frac{-13+12}{14}\) = \(\frac{-1}{14}\) (Therefore, L.C.M of 14 and 7 is 14) (viii) \(\frac{-7}{22}-\frac{-8}{33}\) = \(\frac{-21+16}{66}\) = \(\frac{-55}{66}\) (Therefore, L.C.M of 22 and 33 is 66) |
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