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Sum of n terms of the series √2 + √8 + √18 + √32 + ...... isA. \(\frac{n(n+1)}{2}\)B. 2n (n+1)C. \(\frac{n(n+1)}{\sqrt2}\)D. 1 |
Answer» The given A.P is √2 + √8 + √18 + √32 +.... The simplified A.P. is √2,2√2,3√2,4√2, ....... Here a = √2 d = 2√2 - √2 = √2 Sn = \(\frac{n}{2}\)(2a + (n–1) d) = \(\frac{n}{2}\)(2√2 + (n–1)√2) = √2n/2 (1 + n) = n (n + 1)/√2 |
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