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Suppose `300J` of work done on a system and `70cal`. Of heat heat is extracted from the system. What are the values of `dW , dQ and dU` with proper signs? |
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Answer» As work is done on the system, therefore `dW= -300J` Again as `70 cal.` Of heat is extracted from the system, `:. dQ = -70 cal. = -70xx4.2J` Noe, `dU=dQ-dW` `= -70xx4.2-(-300)J` `dU= -294+300= 6J`. |
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