1.

Suppose that the electric field amplitude of an electromagnetic wave is `E_(0)=120 ` N/C and that its frequency is v=50.0 MHz.Find expressions for E and B.

Answer» Expression for `vecE` is E`=E_(0) sin (kx-omegat)`
`=120 N//c)` Sin [(1.05 rad/m)x=`(3.14xx10^(8)` rad/s `)` t]`hatj`
Expression for `vecB` is B=`B_(0)` sin `(kx-omegat)`
`=(4xx10^(-7)T)sin[(1.05 "rad/m")x-(3.14xx10^(8) "rad/s")t] hatk`.


Discussion

No Comment Found

Related InterviewSolutions