`t_(1//4)` can be taken as the time taken for concentration of reactant to drop to `.^(3)//_(4)` of its initial value. If the rate constant for a first order reaction is `K`, then `t_(1//4)` can be written as:A. 0.10 /KB. 0.29/KC. 0.69/KD. 0.75/K

`t_(1//4)` can be taken as the time taken for concentration of reactan

1.	`t_(1//4)` can be taken as the time taken for concentration of reactant to drop to `.^(3)//_(4)` of its initial value. If the rate constant for a first order reaction is `K`, then `t_(1//4)` can be written as:A. 0.10 /KB. 0.29/KC. 0.69/KD. 0.75/K
Answer» Correct Answer - b `t_(1//4) = (2.303)/(k) "log" (1)/(1 - (1)/(4)) = (0.29)/(k)` .

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`t_(1//4)` can be taken as the time taken for concentration of reactant to drop to `.^(3)//_(4)` of its initial value. If the rate constant for a first order reaction is `K`, then `t_(1//4)` can be written as:A. 0.10 /KB. 0.29/KC. 0.69/KD. 0.75/K

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