1.

`T_(50)` of first order reaction is 10 min. starting with 10 `"mol"^(-1)` rate after 20 min is :A. `0.0693xx"mol" L^(-1)min^(-1)`B. `0.0693xx2.5"mol" L^(-1)min^(-1)`C. `0.0693xx5"mol" L^(-1)min^(-1)`D. `0.0693xx10"mol" L^(-1)min^(-1)`

Answer» Correct Answer - B
Remainin concetration of reactant after 20 min
`=(1)/(4)xx102.5"mol"L^(-1)`
`"Rate"=kxx["Reactant"]=(0.693)/(t_(1//2))xx["Reactant"]`
`=(0.693)/(10xx2.5=0.0693xx2.5 "mol"L^(-1) min^(-1)`


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