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t some temperature, the rate constant for the reaction of the type `2A rarr` Products is `0.08 Ms^(-1)`. The time it takes for the concentration of A to drop from `1.50M to 0.30M` isA. `7.5s`B. `9.5s`C. `11.5s`D. `13.5s` |
Answer» Correct Answer - A From the unit of rate constants `(molL^(-1)s^(-1))` , we can conclude that the reaction is of zero order. For a reaction, `aArarr`products, that is zero order, the integater rate law is `[A]_(t)=[A]_(0)-akt` or `t=[A]_(0)-[A]_(t)//ak` Substituting the valus, we get `t=([(1.50)-(0.30)]M)/((2)(0.08Ms^(-1)))` `=7.5s` |
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