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`(tan^(3)theta-1)/(tantheta-1)`= ________.A. `sec^(2) theta+ tantheta`B. `sec^(2)theta-tantheta`C. 0D. `tantheta-sec^(2)theta` |
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Answer» Correct Answer - A Use `a^(3)-b^(3)=(a-b)(a^(2)+ab+b^(2))`. |
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