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Tan (B + 15°) = 1/√3 then B =A) 60° B) 80° C) 70° D) 15° |
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Answer» Correct option is: D) 15° We have tan (B + \(15^\circ\) ) = \(\frac 1{\sqrt3} \) = tan \(30^\circ\) = B + \(15^\circ\) = \(30^\circ\) = B = \(30^\circ\) - \(15^\circ\) = \(15^\circ\) Correct option is: D) 15° |
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