InterviewSolution
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InterviewSolution
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`tan{(pi)/(4)+1/2cos^(-1)alpha}+tan{(pi)/(4)-1/2cos^(-1)alpha}` `alpha ne 0` is equal toA. `alpha`B. `2alpha`C. `(2)/(alpha)`D. none of these |
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Answer» We have `tan{(pi)/(4)+1/2cos^(-1)alpha}+tan{(pi)/(4)-1/2cos^(-1)alpha}` `tan(pi)/(4)+(theta)/(2)+tan((pi)/(4)-(theta)/(2))` where `theta = cos^(-1)alpha` `=(1+tan(theta)/(2))/(1-tan(theta)/(2))+(1-tan(theta)/(2))/(1+tan(theta)(theta)/(2))=2(1+tan^(2)(theta)/(2))/(1-tan^(2)(theta)/(2))=(2)/(cos theta)=(2)/(alpha)` |
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