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Tangents PA and PB are drawn to the circle `x^2+y^2=4`,then locus of the point P if PAB is an equilateral triangle ,is equal to |
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Answer» `In/_AOD` `cos30=(AD)/(OA)` `AD=ACos30=2*sqrt3/2` `AD=sqrt3` `AB=2sqrt3` `OP^2=OA^2+AP^2` `(h-0)^2+(k-0)^2=4+12` `h^2+k^2=16` `x^2+y^2=16` option A is correct. |
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