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tationalkineticenergy of a body is E. In the |9of external torque, if mass of the bodyis halved and radius of gyration doubled, then itsrotational kinetic energy will be(1) 0.5E (2) 0.25E (3) E (4) 2E |
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Answer» Well, if mass is doubled, K. E is doubled So now K.E1=2K.E When velocity is halved, K.E becomes 1/4th of initial value K.E 2 = K.E1 /4 =2*K.E/4 =K.E/2 =0.5E so, kinetic energy is halved after the changes |
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