1.

tationalkineticenergy of a body is E. In the |9of external torque, if mass of the bodyis halved and radius of gyration doubled, then itsrotational kinetic energy will be(1) 0.5E (2) 0.25E (3) E (4) 2E

Answer»

Well, if mass is doubled, K. E is doubled

So now K.E1=2K.E

When velocity is halved, K.E becomes 1/4th of initial value

K.E 2 = K.E1 /4

=2*K.E/4

=K.E/2 =0.5E

so, kinetic energy is halved after the changes



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