InterviewSolution
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( \text { Force } ) ^ { x } = \frac { ( \operatorname { Mas } s ) ^ { 2 } ( \operatorname { Radius } ) ^ { 2 } } { ( \text { Time period } ) ^ { 4 } } , \text { the value of } x |
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Answer» using dimensional analysis dimension of Force = ML/T² so, (ML/T²)^(x) = (M²)(L)²/T⁴ => (ML/T²)^(x) = (ML/T²)² so, x = 2 option D |
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