1.

( \text { Force } ) ^ { x } = \frac { ( \operatorname { Mas } s ) ^ { 2 } ( \operatorname { Radius } ) ^ { 2 } } { ( \text { Time period } ) ^ { 4 } } , \text { the value of } x

Answer»

using dimensional analysis

dimension of Force = ML/T²

so, (ML/T²)^(x) = (M²)(L)²/T⁴

=> (ML/T²)^(x) = (ML/T²)²

so, x = 2

option D



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