Tha ray of light is incident normally in one surface of a prism of ref

1.	Tha ray of light is incident normally in one surface of a prism of reftacting angle 60. The emergent ray grazes the other refracting surface. Find the refractive index of the prism.
Answer» $\huge\underline{\underline{\bf \orange{Question-}}}$ Tha RAY of light is incident normally in one surface of a prism of reftacting angle 60. The emergent ray grazes the other REFRACTING surface. Find the REFRACTIVE index of the prism. $\huge\underline{\underline{\bf \orange{Solution-}}}$ Tha ray of light is incident normally in one surface of a prism (Given) ⛬ ${\sf r_1}$ = 0 and Prism refracting angle (∠A) = 60° So , $\implies{\sf \red{ r_1+r_2=\angle A} }$ $\implies{\sf 0+ r_2=60°}$ $\implies{\sf \green{ r_2=60°} }$ ${\sf r_2}$ is critical angle for prism ✪ $\large{\boxed{\bf \blue{\mu=\dfrac{1}{sin\theta_c}} }}$ $\implies{\sf \mu=\dfrac{1}{sin\:r_2}}$ $\implies{\sf \mu=\dfrac{1}{sin60°} }$ $\implies{\sf \mu=\dfrac{1}{\sqrt{3}/2}}$ $\implies{\sf \mu=\dfrac{2}{\sqrt{3}} }$ On rationalisation $\implies{\sf \mu=\dfrac{2}{\sqrt{3}}×\dfrac{\sqrt{3}}{\sqrt{3}} }$ $\implies{\sf \mu=\dfrac{2\sqrt{3}}{3}}$ $\implies{\sf \mu=\dfrac{2×1.732}{3} }$ $\implies{\sf \mu= \dfrac{3.46}{3}}$ $\implies{\bf \red{ \mu=1.15 }}$ $\huge\underline{\underline{\bf \orange{Answer-}}}$ Refractive index of the prism is ${\bf \red{1.15}}$ .

Tha ray of light is incident normally in one surface of a prism of reftacting angle 60. The emergent ray grazes the other refracting surface. Find the refractive index of the prism.

Answer»

$\huge\underline{\underline{\bf \orange{Question-}}}$

Tha RAY of light is incident normally in one surface of a prism of reftacting angle 60. The emergent ray grazes the other REFRACTING surface. Find the REFRACTIVE index of the prism.

$\huge\underline{\underline{\bf \orange{Solution-}}}$