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The 10th and 18th terms of an A.P. are 41 and 73 respectively. Find 26th term. |
Answer» a10 = 41 a + (10 – 1)d = 41 a + 9d = 41 …(i) a18 = 73 a + (18 – 1)d = 73 Substituting the value of a from (i), 41 – 9d + 17d = 73 8d = 32 d = 4 a = 41 – 9(4) a = 41 – 36 a = 5 a26 = a + (26 – 1)d = 5 + 25(4) = 5 + 100 = 105 |
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