1.

The 10th and 18th terms of an A.P. are 41 and 73 respectively. Find 26th term.

Answer»

a10 = 41

a + (10 – 1)d = 41

a + 9d = 41 …(i)

a18 = 73

a + (18 – 1)d = 73

Substituting the value of a from (i),

41 – 9d + 17d = 73

8d = 32

d = 4

a = 41 – 9(4)

a = 41 – 36

a = 5

a26 = a + (26 – 1)d

= 5 + 25(4)

= 5 + 100

= 105



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