1.

The 17th term of an AP exceeds its 17th term by 7. Find the common difference.

Answer»

a17 = a10 + 7, d =? 

a + 16d = a + 9d + 7 

a + 16d – a – 9d = 7 

7d = 7

∴ d = \(\frac{7}{7}\)

∴ d = 1



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