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The 17th term of an AP exceeds its 17th term by 7. Find the common difference. |
Answer» a17 = a10 + 7, d =? a + 16d = a + 9d + 7 a + 16d – a – 9d = 7 7d = 7 ∴ d = \(\frac{7}{7}\) ∴ d = 1 |
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