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The 4th term of an AP is 11. The sum of the 5th and 7th terms of this AP is 34. Find its common difference. |
Answer» Let a be the first term and d be the common difference of an AP. an = a + (n – 1)d a4 = a + (4 – 1)d = a + 3d a + 3d = 11 ………(1) Now, a5 = a + 4d and a7 = a + 6d Now, a5 + a7 = a + 4d + a + 6d = 2a + 10d 2a + 10d = 34 a + 5d = 17 ……..(2) Subtracting (1) from (2), we get 2d = 17 – 11 = 6 d = 3 The common difference = 3 |
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