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The 7th term of an A.P. is – 4 and its 13th term is – 16. Find the A.P. |
Answer» We have a7 = a + (7 – 1)d = a + 6d = –4 …(1) and a13 = a + (13 – 1)d = a + 12d = –16 …(2) Solving the pair of linear equations (1) and (2), we get a + 6d – a – 12d = –4 – (–16) ⇒ – 6d = –4 + 16 ⇒ – 6d = 12 ⇒ d = –2 Putting the value of d in eq (1), we get a + 6(–2) = –4 ⇒ a – 12 = –4 ⇒ a = 8 Hence, the required AP is 8, 6, 4, 2,… |
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