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The 7th term of an AP is -4 and its 13th term is -16. Find the AP. |
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Answer» Let us say a be the first term and d be the common difference of an AP an = a + (n – 1)d a7 = a + (7 – 1)d = a + 6d = -4 …………(1) And a13 = a + 12d = -16 …..…..(2) Subtracting equation (1) from (2), we get 6d = -16 – (-4) = -12 From (1), a + 6d = -4 a + (-12) = -4 a = -4 + 12 = 8 a = 8, d = -2 AP will be 8, 6, 4, 2, 0, …… |
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