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The 7th term of an AP is 71. The third term is 43. Find the 4th term.1. 502. 513. 494. 55 |
Answer» Correct Answer - Option 1 : 50 Given: The 7th term of an AP is 71. The third term is 43. Formula used: Nth term of an AP, Tn = a + (n - 1)d, where ‘a’ is the first term, ‘n’ is the total number of terms and ‘d’ is the common difference. Calculation: Let the first term is ‘a’ and common difference is‘d’. T7 = a + (7 – 1)d ⇒ 71 = a + 6d ----(1) T3 = a + (3 – 1)d ⇒ 43 = a + 2d ----(2) From equation from (1) and (2) 71 – 6d = 43 – 2d ⇒ 4d = 28 ⇒ d = 7 And a = 29 Fourth term, T4 = a + 3d ⇒ 29 + 3 × 7 = 50 ∴ required answer is 50. |
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