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The 7th term of the an AP is -4 and its 13th term is -16. Find the AP. |
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Answer» We have T7 = a + (n - 1)d \(\Rightarrow\) a + 6d = -4 ........(1) T13 = a + (n - 1)d \(\Rightarrow\) a + 12d = -16 ........(2) On solving (1) and (2), we get a = 8 and d = -2 Thus, first term = 8 and common difference = -2 ∴ The term of the AP are 8,6,4,2,......... |
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