1.

The 7th term of the an AP is -4 and its 13th term is -16. Find the AP.

Answer»

We have

T7 = a + (n - 1)d

\(\Rightarrow\) a + 6d = -4 ........(1)

T13 = a + (n - 1)d

\(\Rightarrow\) a + 12d = -16 ........(2)

On solving (1) and (2), we get

a = 8 and d = -2

Thus, first term = 8 and common difference = -2

∴ The term of the AP are 8,6,4,2,.........



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