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The 8th term of an A.P. is 37, and its 12th term is 57. Find the A.P. |
Answer» We have a8 = a + (8 – 1)d = a + 7d = 37 …(1) and a12 = a + (12 – 1)d = a + 11d = 57 …(2) Solving the pair of linear equations (1) and (2), we get a + 7d – a – 11d = 37 – 57 ⇒ – 4d = –20 ⇒ d = 5 Putting the value of d in eq (1), we get a + 7(5) = 37 ⇒ a + 35 = 37 ⇒ a = 2 Hence, the required AP is 2, 7, 12, 17,… |
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