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The 9th term of an A.P. is equal to 6 times its second term. If its 5th term is 22, find the A.P. |
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Answer» Given: a5 = 22 a + 4d = 22 (i) Acc. to question, a9 = 6a2 (ii) a9 = a +8d a2 = a+d Putting the value of a9 and a2 in (ii) a +8d = 6(a +d) 2d = 5a 2d = 5(22 - 4d) 22d = 110 d = 5 Now, putting the value of d in (i) a = 22 - 4(5) = 2 a1 = a = 2 a2 = a +d = 2 +5 = 7 a3 = a +2d = 2 + 2(5) = 12 Hence, the A.P. is 2, 7, 12, 17,.......... |
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