The acceleration-displacement graph of a particle moving in a straight line is as shown in figure, initial velocity of particle is zero. Find the velocity of the particle when displacement of the particle is `s=12 m`.

The acceleration-displacement graph of a particle moving in a straight

1.	The acceleration-displacement graph of a particle moving in a straight line is as shown in figure, initial velocity of particle is zero. Find the velocity of the particle when displacement of the particle is `s=12 m`.
Answer» `v^(2)-u^(2)=2ax` `impliesax=(v^(2)-u^(2))/(2)=(v^(2))/(2)-(u^(2))/(2)` `because(u=0)` `impliesv=sqrt(2("area under a-x graph"))` Area under `a-x` graph Area of `DeltaOAE+` area of reactangle `ABEF` `+` area of trapenzium BFGC + Area of `DeltaCGD` Area `=(1)/(2)(2)(2)+6xx2+(1)/(2)(2+4)(2)+(1)/(2)xx2xx4=24` `impliesv=sqrt(2xx24)=4sqrt(3) m//s`

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The acceleration-displacement graph of a particle moving in a straight line is as shown in figure, initial velocity of particle is zero. Find the velocity of the particle when displacement of the particle is `s=12 m`.

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