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InterviewSolution
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The activity of a radioactive sample decreases to `1//3` of the original activity, `A_(0)` in a period of 9 years. After 9 years more, its activity `A_(0)//x`. Find the value of `x`. |
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Answer» Correct Answer - `9` `t = (2.303)/(lambda) log (A_(0))/(A_(1)0` `9 = (2.303)/(lambda) log 3 implies lambda = 0.122` `18 = (2.303)/(0.122) log (A_(0))/(A_(2))` `(A_(2))/(A_(0)) = (1)/(9), :. A_(2) = (A_(0))/(9) ("given" (A_(0))/(x))` `:. X = 9` |
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