InterviewSolution
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InterviewSolution
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The activity of a radioactive substance is `R_(0)` at `t = 0`, `R_(1)` at `t = t` and `R_(2)` at `t = 2t`. The decay constant of this species is/are given by:A. `(log_(e) R_(1) - log_(e) R_(2))/(t)`B. `(log_(e) R_(0) - log_(e) R_(1))/(t)`C. `(log_(e) R_(2) - log_(e) R_(1))/(2t)`D. `(log_(e) R_(0) - log_(e) R_(1))/(2t_(2))` |
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Answer» Correct Answer - `(a,b,d)` `R_(1) = R_(0) e^(-lambda t)` `R_(2) = R_(0) e^(-lambda 2t)` `:. (R_(1))/(R_(2)) = e^(-lambda t)` or `lambda = (log_(e) R_(1) - log_(e) R_(2))/(t)` Similarly, `lambda = (log_(e) R_(0) - log_(e) R_(1))/(t)` `lambda =(log_(e) R_(0) - log_(e) R_(2))/(2t)` |
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