The ages of three boys are consecutive odd numbers. The ratio of the a

1.	The ages of three boys are consecutive odd numbers. The ratio of the ages of the youngest and the oldest 5 years ago was 4 : 5. Find the age of the middle one, two years hence.1. 27 years2. 21 years3. 24 years4. 25 years5. 23 years
Answer» Correct Answer - Option 4 : 25 years GIVEN: Ages are consecutive odd numbers. Youngest : Oldest (5 years ago) = 4 : 5 EXPLANATION: Let the ages be x, x + 2, x + 4 A.T.Q (x - 5)/(x + 4 - 5) = 4/5 ⇒ 5x - 25 = 4x - 4 ⇒ x = 21 years Required age = 21 + 2 + 2 = 25 years ∴ The answer is 25 years.

The ages of three boys are consecutive odd numbers. The ratio of the ages of the youngest and the oldest 5 years ago was 4 : 5. Find the age of the middle one, two years hence.1. 27 years2. 21 years3. 24 years4. 25 years5. 23 years

Answer» Correct Answer - Option 4 : 25 years

GIVEN:

Ages are consecutive odd numbers.

Youngest : Oldest (5 years ago) = 4 : 5

EXPLANATION:
Let the ages be x, x + 2, x + 4

A.T.Q

(x - 5)/(x + 4 - 5) = 4/5

⇒ 5x - 25 = 4x - 4

⇒ x = 21 years

Required age = 21 + 2 + 2 = 25 years

∴ The answer is 25 years.

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The ages of three boys are consecutive odd numbers. The ratio of the ages of the youngest and the oldest 5 years ago was 4 : 5. Find the age of the middle one, two years hence.1. 27 years2. 21 years3. 24 years4. 25 years5. 23 years

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