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InterviewSolution
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The amount of heat supplied to `4xx10^(-2)` kg of nitrogen at room temperature to rise its temperature by `50^(@)C` at constant pressure is (Molecualr mass of nitrogen is 28 and `R= 8.3 J mol^(-1)K^(-1))`A. 2.08 KJB. 3.08 KJC. 4.08 KJD. 5.08 KJ |
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Answer» Correct Answer - A Given , `m=4xx10^(-2)kg =40 g. DeltaT=50^(c )` Number of moles ,`n=(m)/(M)=(40)/(28)=1.43` As nitrogen is a diatomic gas, molar specific heat at contstant pressure is `C_(p)=(7)/(2)R=(7)/(2)xx8.3 J mol^(-1) K^(-1)=29.05 J mol^(-1) K^(-1)` As `DeltaQ =nC_(p)DeltaT` `DeltaQ=1.43xx29.05xx50=2.08xx10^(3)` J =2 2.08KJ |
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