InterviewSolution
Saved Bookmarks
| 1. |
The amplitude of S.H.M. at antinodes of the problem No. 51 isA. 0.01 mB. `(sqrt(3)//2)xx0.02m`C. 0.02mD. `0.02xx1.714` |
|
Answer» Correct Answer - C `R_("max") = 2A = 2xx0.1=0.02` |
|