1.

The amplitude of S.H.M. at antinodes of the problem No. 51 isA. 0.01 mB. `(sqrt(3)//2)xx0.02m`C. 0.02mD. `0.02xx1.714`

Answer» Correct Answer - C
`R_("max") = 2A = 2xx0.1=0.02`


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