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The amplitude of S.H.M. at x=0.05 m isA. 0.02 mB. 0.01 mC. 0.0141mD. 1.414 m

Answer» Correct Answer - C
`R=2A cos (2pix)/(0.4)==0.02cos((2pixx0.05)/(0.4))`
`=0.02cospi/4=0.02xx(1)/(sqrt2)=0.0141m`


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