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The angular displacement of a particle is given by `theta =t^3 + t^2 + t +1` then, its angular velocity at `t=2` sec is …… `rad s^(-1)`A. `27`B. `17`C. `15`D. `16` |
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Answer» Correct Answer - B `theta=t^(3)+t^(2)+t+1,omega=(dtheta)/(dt)=3t^(2)+2t+1` |
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