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The angular displacement of a particle is given by `theta =t^3 + t^2 + t +1` then,the angular acceleration of the particle at `t=2` sec is …….`rad s^(-2)A. `14`B. `16`C. `18`D. `24` |
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Answer» Correct Answer - A `alpha=(domega)/(dt)=6t+2=12+2=14 rad s^(-2)` |
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