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The angular momentum of rotating body is increased by `20%`. What will be the increase in its rotational kinetic energy? |
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Answer» Kinetic energy `KE=(L^(2))/(2I)rArrE propL^(2)` `(DeltaE)/E=(120/100)^(2) (or) (DeltaE)/D=0.44` `(DeltaE)/Exx100=44%` |
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