1.

The angular momentum of rotating body is increased by `20%`. What will be the increase in its rotational kinetic energy?

Answer» Kinetic energy `KE=(L^(2))/(2I)rArrE propL^(2)`
`(DeltaE)/E=(120/100)^(2) (or) (DeltaE)/D=0.44`
`(DeltaE)/Exx100=44%`


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