1.

The annual increase in the population of a town is 10%. If the present population of the town is 180000, then what will be its population after two years ?

Answer»

Population after two years = 180000\(\big(1+\frac{10}{100}\big)^2\)

= 180000 x \(\big(\frac{11}{10}\big)^2\) = 180000 x \(\frac{121}{100}\) = 217800.



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