1.

The annual rate of growth in population of a town is 10%. If its present population is 33275, what was it 3 years ago? A. Rs. 25000 B. Rs. 27500 C. Rs. 30000 D. Rs. 26000

Answer»

Let 3 years ago population = P 

Present population = 33275 

Time, n = 3 years 

Increases rate, R = 10% per annum 

Now, 

Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest 

P = Present value 

R = Annual interest rate 

n = Time in years] 

∴ Population = P (1 + R/100)

⇒ 33275 = P (1 + 10/100)

⇒ 33275 = P (1 + 1/10)3 

⇒ 33275 = P (11/10)3 

⇒ 33275 = P × 1331/1000 

⇒ P = 33275 × 1000/1331 

⇒ P = 25 × 1000 

⇒ P = 25000 

∴ 3 years ago population is 25000.



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