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The annual rate of growth in population of a town is 10%. If its present population is 33275, what was it 3 years ago? A. Rs. 25000 B. Rs. 27500 C. Rs. 30000 D. Rs. 26000 |
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Answer» Let 3 years ago population = P Present population = 33275 Time, n = 3 years Increases rate, R = 10% per annum Now, Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest P = Present value R = Annual interest rate n = Time in years] ∴ Population = P (1 + R/100)n ⇒ 33275 = P (1 + 10/100)3 ⇒ 33275 = P (1 + 1/10)3 ⇒ 33275 = P (11/10)3 ⇒ 33275 = P × 1331/1000 ⇒ P = 33275 × 1000/1331 ⇒ P = 25 × 1000 ⇒ P = 25000 ∴ 3 years ago population is 25000. |
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