InterviewSolution
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The apparent frequency is `f_(1)` when a souece of sound approches a stationary obsever with a speed u and `f_(2)` when the observe approaches the stationary source with same speed. If v is the velocity of sound, thenA. `f_(1)=f_(2)`B. `f_(1) gt f_(2) if u ltv`C. `f_(2) gt f_(1) if u ltv`D. `f_(2) gt f_(1) if u ltv` |
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Answer» Correct Answer - D `f_(1)=((v)/(v-v_(s)))f=((v)/(v-v))f=[((1)/(1-u/v))]f` When observer approaches towards the source `f_(2)=((v+v_(o))/(v))f=((v+u)/(v))f=(1-u/v)f` `therefore" "f_(2) gt f_(1)` |
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