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The area bounded by the coordinate axes and normal to the curve `y=log_(e)x` at the point P( 1 , 0), isA. 1 sq. unitB. 2 sq. unitsC. `(1)/(2)` sq. unitD. none of these |
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Answer» Correct Answer - C We have, `y=log_(e)x rArr (dy)/(dx) = (1)/(x) rArr ((dy)/(dx)) _(p) = 1` The equation of the normal at (1, 0) is `y-0= -1 (x-1) rArr x+y=1` Clearly, it makes a triangle of area `(1)/(2)` sq. unit with the coordinate axes. |
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