1.

The area of a trapezium is 475 `cm^(2)` and its height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.

Answer» Correct Answer - 23 cm, 27 cm
Let the parallel sides be x cm and (x + 4) cm. Then,
`(1)/(2)xx[x+(x+4)]xx 19 = 475 rArr 2x + 4 = (475 xx 2)/(19) rArr 2x = 46 rArr x = 23`.


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